![]() As discussed previously, all applied forces and moments are translated to the centroid of the bolt pattern. (b+d) 4 - 6b 2 d 2 /12 (b+d) 1,04.10 6 mm 4 /mm.(From Table) It is necessary to locate the point subject to the highest shear stress.For a weld subject to only torsion this would be simply at the point furthest from the COG. It should be noted that these calculations are directly analogous to the calculation of the moment of inertia of a cross section and polar moment of inertia of a cross section. Sol: The given plate is symmetrical about the y-y axis, therefore \ = 150 mm. A 250-27 223mm Moment M P.r 10000.223 2,23.10 6 N.mm J u Polar Moment of inertia for weld 1unit(mm) thick. To find \, we have to divide the whole Figure into standard areas.Įxample: Find the moment of inertia of a plate with a circular hole about its centroidal x axis as shown in Fig.8. You may simply rotate the member by 90 degrees and recalculate, always remembering the original position of the Member. ![]() However, it is crucial that b and h are assigned correct values. Sol: The given I-section is symmetrical about the y-y axis, therefore, Solution: The moment of inertia of a rectangular shape such as this one is easily calculated by using the equation I 1/12 bh3. = + Įxample: Determine the moment of inertia about the horizontal axis passing through the centroid of the section as shown in Fig.7.
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